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Algebra / Linear functions Difficulty: Hard

The equation $h = \frac{9 (v - 273.15)}{5} + 32$ gives the corresponding temperature $h$ , in degrees Fahrenheit, of any substance that has a temperature of $v$ kelvins, where $v greater than 0$ . If a substance has a temperature of $467.33$ degrees Fahrenheit, what is the corresponding temperature, in kelvins, of this substance?

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Explanation

The correct answer is $515$ . It’s given that the equation $h = \frac{9 (v - 273.15)}{5} + 32$ gives the corresponding temperature $h$ , in degrees Fahrenheit, of any substance that has a temperature of $v$ kelvins, where $v greater than 0$ . Substituting $467.33$ for $h$ in the given equation yields $467.33 = \frac{9 (v - 273.15)}{5} + 32$ . Subtracting $32$ from both sides of this equation yields $435.33 = \frac{9 (v - 273.15)}{5}$ . Multiplying both sides of this equation by $5$ yields $2,176.65 = 9 (v - 273.15)$ . Dividing both sides of this equation by $9$ yields $241.85 = v - 273.15$ . Adding $273.15$ to both sides of this equation yields $515 equals v$ . Therefore, if a substance has a temperature of $467.33$ degrees Fahrenheit, the corresponding temperature, in kelvins, of this substance is $515$ .